Wrong
The cost given would be the cost if every single one of the possible combinations was tried. Assuming a brute force attack consists of first trying "aaaaaaaaaa" then "aaaaaaaaab" then this would only be true if the password was "zzzzzzzzzz" - which is unlikely.
Then again, are crackers clever enough to use random attacks? Sounds like 'zzzzzzzzzz' is going to become my password of choice from now on.