more maths
So if its total energy capacity (at infinity) is 3.3Wh then its initial energy output would be 2.6 µW.
based on 100.1 year half life.
If its initial energy output is 10µW then its lifetime energy output will be 12.7Wh
-P_0 * t_half/ln(0.5) = E_life
where P_0 is power output in Watts at start, t_half is the half life in seconds and E_life is the lifetime energy output in Joules.
Of course reading the paper would just be cheating :o).
Any way, looks like they are doing this somewhere in between, and there is a bit more to it.
Biting the hand that feeds IT
