Re: What did you expect?
That's based on the invalid assumption that a display needs to be as bright as the sun to be visible in sunlight. You need 700 nits (Cd/M^2) to be visible properly in sunlight (source: https://mytechdecisions.com/video/understanding-brightness-in-outdoor-displays/ ), which converts to 0.00010248901903367w/cm^2 (source: http://online.unitconverterpro.com/conversion-tables/convert-alpha/factors.php?cat=luminance&unit=13&val=700). That's 0.0030746705710101w for a 30cm^2 panel. Even assuming a rather low efficiency we should be under 1w.