Re: @Chemist...
"I'll try to explain this one more time... Draw two points A and B. Draw a straight line connecting A and B. now draw some point C that is in between A and B but does not lie on the line. You can now draw a curve ACB. The curve represents the path of space so gravity, light, etc... Travels along that path."
What do you mean by "the path of space"? Is the paper itself space, and the curve a path through it? Or is it only that curve that's space?
"Now if neutrinos are not effected by gravity, then they will travel along AB."
If the paper is space, and you're imagining that spacetime curvature is that paths through it are curved like your ACB curve, then you've simply got it wrong.
Spacetime curvature is where the piece of paper itself is curved, like the surface of a ball or saddle. Try to draw two, straight, parallel lines on such noneuclidean paper, and they'll diverge or converge instead of remaining parallel. Lines of longitude are an example of this. The lines are dead straight, in the sense that someone walking along them wouldn't veer left or right, yet they're parallel at the equator, and converge towards the poles.
With curved spacetime, it's not a case of light, etc, following a curved path like your ACB curve. Instead, light, and everything else moving inertially (no externally applied forces acting on them) follows a straight path, straight from A to B. Just like walking all the way along the Greenwich Meridian from the north pole to the south pole.
But if, instead, you mean that only your ACB curve represents space, rather than the whole sheet of paper, then what you're suggesting is that the neutrinos are leaving space at one point, A, and re-entering space at another point, B. That's not simply a matter of neutrinos not being "effected by gravity" [sic], it's something way beyond that.